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Manchester | 26-SDC-Jun | Fithi Teklom | Sprint 1 | Analyse And Refactor Functions #259
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,14 +1,30 @@ | ||
| /** | ||
| * Finds common items between two arrays. | ||
| * | ||
| * Time Complexity: | ||
| * Space Complexity: | ||
| * Optimal Time Complexity: | ||
| * Time Complexity: O(n * m), where as well as m referes to a size — checks each item in the first array against items in the second array. | ||
| * Space Complexity: O(n) — creates a filtered array and a Set. | ||
| * Optimal Time Complexity: O(n + m) — each array can be checked in linear time using a Set. | ||
| * | ||
| * @param {Array} firstArray - First array to compare | ||
| * @param {Array} secondArray - Second array to compare | ||
| * @returns {Array} Array containing unique common items | ||
| */ | ||
| export const findCommonItems = (firstArray, secondArray) => [ | ||
| ...new Set(firstArray.filter((item) => secondArray.includes(item))), | ||
| ]; | ||
| export const findCommonItems = (firstArray, secondArray) => { | ||
| const secondSet = new Set(secondArray); | ||
| const commonItems = new Set(); | ||
|
|
||
| for (const item of firstArray) { | ||
| if (secondSet.has(item)) { | ||
| commonItems.add(item); | ||
| } | ||
| } | ||
|
|
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| return [...commonItems]; | ||
| } | ||
|
|
||
| /** | ||
| After Refactoring | ||
| * Time Complexity: O(n + m) — uses a Set to check for common items efficiently. | ||
| * Space Complexity: O(m + q) — stores items from the second array and the common items, where q is the number of unique matches. | ||
| * Optimal Time Complexity: O(n + m) — each array is processed in linear time. | ||
| */ | ||
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,21 +1,32 @@ | ||
| /** | ||
| * Find if there is a pair of numbers that sum to a given target value. | ||
| * | ||
| * Time Complexity: | ||
| * Space Complexity: | ||
| * Optimal Time Complexity: | ||
| * Time Complexity: O(n²) — nested loops check pairs of numbers. | ||
| * Space Complexity: O(1) — uses only a fixed number of variables. | ||
| * Optimal Time Complexity:O(n) — a Set can find a matching pair in one pass, on average. | ||
| * | ||
| * @param {Array<number>} numbers - Array of numbers to search through | ||
| * @param {number} target - Target sum to find | ||
| * @returns {boolean} True if pair exists, false otherwise | ||
| */ | ||
| export function hasPairWithSum(numbers, target) { | ||
| for (let i = 0; i < numbers.length; i++) { | ||
| for (let j = i + 1; j < numbers.length; j++) { | ||
| if (numbers[i] + numbers[j] === target) { | ||
| return true; | ||
| } | ||
| const seen = new Set(); | ||
| for (const number of numbers) { | ||
| const needed = target - number; | ||
|
|
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| if (seen.has(needed)) { | ||
| return true; | ||
| } | ||
|
|
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| seen.add(number); | ||
| } | ||
|
|
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| return false; | ||
| } | ||
|
|
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| /* | ||
| After Refactoring | ||
| * Time Complexity: O(n) — checks each number once on average. | ||
| * Space Complexity: O(n) — stores numbers in a Set. | ||
| * Optimal Time Complexity: O(n) — one pass using a Set, on average. | ||
| */ |
38 changes: 11 additions & 27 deletions
38
Sprint-1/JavaScript/removeDuplicates/removeDuplicates.mjs
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,36 +1,20 @@ | ||
| /** | ||
| * Remove duplicate values from a sequence, preserving the order of the first occurrence of each value. | ||
| * | ||
| * Time Complexity: | ||
| * Space Complexity: | ||
| * Optimal Time Complexity: | ||
| * Time Complexity: O(n²),the nested loops may compare many items against one another. | ||
| * Space Complexity:O(n) — stores the unique items in a new array. | ||
| * Optimal Time Complexity: O(n) — a Set can check for duplicates in one pass, on average. | ||
| * | ||
| * @param {Array} inputSequence - Sequence to remove duplicates from | ||
| * @returns {Array} New sequence with duplicates removed | ||
| */ | ||
| export function removeDuplicates(inputSequence) { | ||
| const uniqueItems = []; | ||
|
|
||
| for ( | ||
| let currentIndex = 0; | ||
| currentIndex < inputSequence.length; | ||
| currentIndex++ | ||
| ) { | ||
| let isDuplicate = false; | ||
| for ( | ||
| let compareIndex = 0; | ||
| compareIndex < uniqueItems.length; | ||
| compareIndex++ | ||
| ) { | ||
| if (inputSequence[currentIndex] === uniqueItems[compareIndex]) { | ||
| isDuplicate = true; | ||
| break; | ||
| } | ||
| } | ||
| if (!isDuplicate) { | ||
| uniqueItems.push(inputSequence[currentIndex]); | ||
| } | ||
| } | ||
|
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| return uniqueItems; | ||
| return [...new Set(inputSequence)]; | ||
| } | ||
|
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| /* | ||
| After Refactoring | ||
| *Time Complexity: O(n) — uses a Set, on average. | ||
| * Space Complexity: O(n) — stores unique items in a new collection. | ||
| * Optimal Time Complexity: O(n) — each input item must be checked. | ||
| */ |
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Note:
Most Set implementations support the common set operations such as union, intersection, difference, subset, superset, equality, add, remove, contains, size, clear, and is empty.
You could consider taking advantage of them for optimal performance.