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The default V8 platform pool of 4 worker threads is created during bootstrap. Most processes are I/O bound and never need that parallelism, but still pay for the extra threads and address space. Default the pool to 1. --v8-pool-size=0 still sizes the pool from available parallelism. Assisted-by: Cursor Grok 4.6 Co-authored-by: Yagiz Nizipli <anonrig@users.noreply.github.com>
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The default V8 platform pool of 4 workers is created at bootstrap. Most processes are I/O bound and still pay for those threads and their address space.
Default
--v8-pool-sizeto 1.--v8-pool-size=0still sizes the pool from available parallelism.Benchmarks
Same binary, default (1) vs
--v8-pool-size=4. Snapshot-less local build (--without-intl --without-node-snapshot). Relative comparison.Threads and memory (
/proc/self/status)--v8-pool-size=4node-V8WorkerThread names at default:
node-MainThread, 1×node-V8Worker,DelayedTaskSchedulerWorker,SignalInspector.Startup
Wall clock (n=50, warmup=8):
--v8-pool-size=4node -e ''empty.mjsbenchmark/misc/startup-core.jsn=30mode=process(ops/sec, higher is better):--v8-pool-size=4empty.mjsrequire-builtins.jsStartup is within noise. The win is thread count and virtual address space (about 216 MB less VmSize). Cluster / many Node processes multiply that.
Restore the old default with
--v8-pool-size=4or--v8-pool-size=0.