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audit: #1016 surrogate horizon is n ≤ q, first difference at q+1 - #1086
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…first difference at q+1 DEPENDENCY-AUDIT.md negative control 1 said the finite cyclic surrogate agrees for n < q and diverges at 2q. #1016 (merged b2e053f, BOUNDARY-CONTROLS.md) derives agreement through every n <= q and a first difference at n = q+1, where b_{q+1} xor b_q = b_1 xor b_0 in every realization. Owner-approved follow-up (chat, 2026-11-04). Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_013T6pfKuv5mi3MXtKjH2tZb
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Accepted head:
45bdf875bfcf82a6358fcf61dddf8fd455bd1408.This is the small follow-up to #1016 that the owner approved, kept separate from #1016's approved head.
One file, one sentence. Negative control 1 in
verification/audits/manuscript/observer-relative-finiteness-20261030/DEPENDENCY-AUDIT.md:n<qbut diverges at2q"n ≤ qand first differs atn = q+1"Source: #1016, merged as
b2e053f3, fileverification/programmes/substratum/continuous-substates/BOUNDARY-CONTROLS.md. The infinite stream and the finite cyclic register have the same visible law for every n ≤ q. At n = q+1, b_{q+1}⊕b_q = b_1⊕b_0 holds in every realization of the register; in the infinite stream these are independent fair bits.What the review checked:
legacy-records.json, and no receipt or seal covers it.Mergeability against current main
f2feecc1: no conflict, and #1085 did not touch this file.🤖 Generated with Claude Code
https://claude.ai/code/session_013T6pfKuv5mi3MXtKjH2tZb