diff --git a/problems/1331-rank-transform-of-an-array/analysis.md b/problems/1331-rank-transform-of-an-array/analysis.md
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+# 1331. Rank Transform of an Array
+
+[LeetCode Link](https://leetcode.com/problems/rank-transform-of-an-array/)
+
+Difficulty: Easy
+Topics: Array, Hash Table, Sorting
+Acceptance Rate: 71.4%
+
+## Hints
+
+### Hint 1
+
+The rank of an element only depends on how many *distinct* values are smaller than it. Think about what happens if you look at the values in sorted order — the smallest distinct value gets rank 1, the next distinct value gets rank 2, and so on. Which two classic tools let you both order the data and remember a mapping?
+
+### Hint 2
+
+You need to preserve the original positions while assigning ranks based on sorted order. A common trick: work on a *copy* of the array, sort the copy, then build a lookup (hash map) from each value to its rank. Finally, walk the original array and replace each element via the lookup.
+
+### Hint 3
+
+Equal elements must share a rank, and ranks must be "as small as possible" (no gaps). So when you scan the sorted copy, only assign a new rank when you encounter a value you haven't seen before. Storing `value -> rank` in a map means duplicates naturally map to the same rank, and the rank counter increments exactly once per distinct value.
+
+## Approach
+
+The rank of an element is `1 + (number of distinct values strictly smaller than it)`. This gives us a clean, deterministic way to compute every rank.
+
+Step by step:
+
+1. **Copy and sort.** Make a copy of `arr` and sort the copy in ascending order. We sort a copy so the original indices are preserved for the final pass.
+2. **Build the rank map.** Iterate over the sorted copy. Maintain a running `rank` starting at 1. For each value, if it is not already a key in the map, insert `value -> rank` and then increment `rank`. Because the array is sorted, all occurrences of a value are contiguous, so the first time we see a value it receives the smallest possible rank, and subsequent duplicates are skipped (they'd map to the same value anyway).
+3. **Rebuild the answer.** Create a result slice the same length as `arr`. For each original element, look up its rank in the map and store it at the same index.
+
+Example with `arr = [37,12,28,9,100,56,80,5,12]`:
+
+- Sorted copy: `[5,9,12,12,28,37,56,80,100]`
+- Rank map (assigned on first sight): `5->1, 9->2, 12->3, 28->4, 37->5, 56->6, 80->7, 100->8`
+- Map back over the original: `[5,3,4,2,8,6,7,1,3]` ✅
+
+The map handles duplicates for free (both `12`s map to rank 3), and sorting guarantees the "as small as possible" requirement since ranks are assigned in increasing value order with no gaps.
+
+## Complexity Analysis
+
+Time Complexity: O(n log n) — dominated by sorting the copy. Building the map and rebuilding the result are each O(n).
+Space Complexity: O(n) — the sorted copy, the value→rank map, and the result slice each use O(n) space.
+
+## Edge Cases
+
+- **Empty array (`arr.length == 0`).** The constraints allow a length-0 array. The code should return an empty (non-nil is nice but not required) slice without indexing errors. Sorting an empty copy and looping zero times handles this naturally.
+- **Single element.** Always maps to rank 1; a good sanity check that the counter starts at 1.
+- **All equal elements (e.g. `[100,100,100]`).** Every element must share the same rank `1`. The map ensures the value is inserted once, so all positions resolve to rank 1.
+- **Negative values and full int range (`-10^9 .. 10^9`).** Ranks are based on relative ordering, not magnitude, so negatives work the same as positives — no special handling needed. Values comfortably fit in Go's `int`.
+- **Already sorted / reverse sorted input.** Doesn't change correctness; it's just a specific ordering the general algorithm already covers.
diff --git a/problems/1331-rank-transform-of-an-array/problem.md b/problems/1331-rank-transform-of-an-array/problem.md
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+---
+number: "1331"
+frontend_id: "1331"
+title: "Rank Transform of an Array"
+slug: "rank-transform-of-an-array"
+difficulty: "Easy"
+topics:
+  - "Array"
+  - "Hash Table"
+  - "Sorting"
+acceptance_rate: 7143.3
+is_premium: false
+created_at: "2026-07-12T04:05:50.492583+00:00"
+fetched_at: "2026-07-12T04:05:50.492583+00:00"
+link: "https://leetcode.com/problems/rank-transform-of-an-array/"
+date: "2026-07-12"
+---
+
+# 1331. Rank Transform of an Array
+
+Given an array of integers `arr`, replace each element with its rank.
+
+The rank represents how large the element is. The rank has the following rules:
+
+  * Rank is an integer starting from 1.
+  * The larger the element, the larger the rank. If two elements are equal, their rank must be the same.
+  * Rank should be as small as possible.
+
+
+
+ 
+
+**Example 1:**
+    
+    
+    **Input:** arr = [40,10,20,30]
+    **Output:** [4,1,2,3]
+    **Explanation** : 40 is the largest element. 10 is the smallest. 20 is the second smallest. 30 is the third smallest.
+
+**Example 2:**
+    
+    
+    **Input:** arr = [100,100,100]
+    **Output:** [1,1,1]
+    **Explanation** : Same elements share the same rank.
+    
+
+**Example 3:**
+    
+    
+    **Input:** arr = [37,12,28,9,100,56,80,5,12]
+    **Output:** [5,3,4,2,8,6,7,1,3]
+    
+
+ 
+
+**Constraints:**
+
+  * `0 <= arr.length <= 105`
+  * `-109 <= arr[i] <= 109`
diff --git a/problems/1331-rank-transform-of-an-array/solution.go b/problems/1331-rank-transform-of-an-array/solution.go
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+package main
+
+import "sort"
+
+// arrayRankTransform replaces each element with its rank.
+//
+// Approach: the rank of a value equals 1 plus the number of distinct values
+// strictly smaller than it. We sort a copy of the array, then walk it once to
+// build a value -> rank map, assigning a new rank only when we meet a value we
+// have not seen before (so equal values share a rank and there are no gaps).
+// Finally we map the original array back through the lookup, preserving order.
+//
+// Time: O(n log n) for the sort. Space: O(n) for the copy, map, and result.
+func arrayRankTransform(arr []int) []int {
+	sorted := make([]int, len(arr))
+	copy(sorted, arr)
+	sort.Ints(sorted)
+
+	rankOf := make(map[int]int, len(sorted))
+	rank := 1
+	for _, v := range sorted {
+		if _, seen := rankOf[v]; !seen {
+			rankOf[v] = rank
+			rank++
+		}
+	}
+
+	result := make([]int, len(arr))
+	for i, v := range arr {
+		result[i] = rankOf[v]
+	}
+	return result
+}
diff --git a/problems/1331-rank-transform-of-an-array/solution_test.go b/problems/1331-rank-transform-of-an-array/solution_test.go
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index 0000000..180ef4c
--- /dev/null
+++ b/problems/1331-rank-transform-of-an-array/solution_test.go
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+package main
+
+import (
+	"reflect"
+	"testing"
+)
+
+func TestSolution(t *testing.T) {
+	tests := []struct {
+		name     string
+		input    []int
+		expected []int
+	}{
+		{
+			name:     "example 1: distinct increasing ranks",
+			input:    []int{40, 10, 20, 30},
+			expected: []int{4, 1, 2, 3},
+		},
+		{
+			name:     "example 2: all equal share rank",
+			input:    []int{100, 100, 100},
+			expected: []int{1, 1, 1},
+		},
+		{
+			name:     "example 3: duplicates with mixed order",
+			input:    []int{37, 12, 28, 9, 100, 56, 80, 5, 12},
+			expected: []int{5, 3, 4, 2, 8, 6, 7, 1, 3},
+		},
+		{
+			name:     "edge case: empty input",
+			input:    []int{},
+			expected: []int{},
+		},
+		{
+			name:     "edge case: single element",
+			input:    []int{42},
+			expected: []int{1},
+		},
+		{
+			name:     "edge case: negative values",
+			input:    []int{-5, -10, 0, -10, 5},
+			expected: []int{2, 1, 3, 1, 4},
+		},
+		{
+			name:     "edge case: reverse sorted",
+			input:    []int{9, 7, 5, 3, 1},
+			expected: []int{5, 4, 3, 2, 1},
+		},
+	}
+
+	for _, tt := range tests {
+		t.Run(tt.name, func(t *testing.T) {
+			result := arrayRankTransform(tt.input)
+			if !reflect.DeepEqual(result, tt.expected) {
+				t.Errorf("arrayRankTransform(%v) = %v, want %v", tt.input, result, tt.expected)
+			}
+		})
+	}
+}