# Dictionaries

Author: MontessoriVisualization

getStarted/python/01python/09_list.py

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+#list is python 
+student_present=["sunday","monday","tuesday"]
+print(student_present[0])
+student_present[0]="sunday morning"
+print(student_present)
+#length
+print(len(student_present))
+
+#appending
+student_present.append("wednesday")
+print(student_present[-1])
+
+#slicing
+#[sunday morning, monday, tuesday, wednesday]
+print(student_present[1:3]) # this will give us a new list with the elements from index 1 to index 2 (3 is not included)
+
+#negativve slicing
+print(student_present[-3:-1]) # this will give us a new list with the elements from index -3 to index -2 (-1 is not included)
+
+list1=[1,2,3]
+list2=list1[:] # this will give us a new list with the same elements as list1 but it will be a different list in memory
+print(list1)
+print(list2)
+list1.append(4)
+print(list1)
+print(list2) # this will also give us [1,2,3,4] because list1 and list2 are pointing to the same list in memory
+
+
+list1[0] = [10,20,30]
+print(list1)
+print(list2)
+print(list1[0][0]) # this will give us 10
+
+#insert
+student_present.insert(1,"thursday")
+print(student_present)
+
+
+#extend
+friends_list1=["ram","shyam","hari"]
+friends_list2=["sita","gita","radha"]
+friends_list1.extend(friends_list2)
+print(friends_list1)
+print(friends_list2)
+
+#remove
+friends_list1.remove("shyam")
+print(friends_list1)#does not include shyam
+
+#pop
+print(friends_list1.pop()) # this will remove the last element from the list and return it
+print(friends_list1)
+poped_friend=friends_list1.pop(1) # this will remove the element at index 1 and return it
+print(friends_list1)
+print(poped_friend)
+
+
+#del
+del friends_list1[0] # this will remove the element at index 0 from the list
+print(friends_list1)
+del friends_list2 # this will delete the entire list from memory
+
+# print(friends_list2) # this will give us an error because friends_list2 has been deleted from memory
+
+#clear
+friends_list1.clear() # this will remove all the elements from the list but the list itself will still exist in memory
+print(friends_list1) # this will give us an empty list []
+
+#copy list
+list3=list1.copy() # this will give us a new list with the same elements as list1 but it will be a different list in memory
+list3=list1[:] # this will also give us a new list with the same elements as list1 but it will be a different list in memory
+
+#adding and extend
+list4=[1,2,3]
+list5=[4,5,6]
+list6=list4+list5 # this will give us a new list with the elements of list4 and list5
+print(list6)
+list4.extend(list5) # this will add the elements of list5 to the end of list4
+print(list4)
+

getStarted/python/01python/10_tupuple.py

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+#int
+tup1=(1, 2, 3, 4, 5)
+tup2=(6, 7, 8, 9, 10)
+print(tup1[0]) # this will give us the first element of the tuple which is 1
+print(tup1[-1]) # this will give us the last element of the tuple which
+print(tup1[0:3]) # this will give us a new tuple with the elements from index 0 to index 2 (3 is not included)
+print(tup1[-3:-1]) # this will give us a new tuple with the
+
+tup3= tup1 + tup2 # this will give us a new tuple with the elements of tup1 and tup2
+tup2= tup2 * 100 # this will give us a new tuple with the elements of tup2 repeated twice
+print(tup3)
+print(tup2)
+
+#unpacking a tuple
+tup4=(1, 2, 3)
+(a, b, c) = tup4 # this will unpack the elements of the tuple into the variables a, b, and c
+print(a) # this will give us 1
+print(b) # this will give us 2
+print(c) # this will give us 3
+
+tup5=(1, 2, 3, 4, 5)
+(a, b, *rest) = tup5 # this will unpack the first two elements of
+# the tuple into the variables a and b, and the rest of the elements into the variable rest
+print(a) # this will give us 1
+print(b) # this will give us 2
+print(rest) # this will give us [3, 4, 5] because the rest of the elements are stored in a list
+
+
+#mutating tuple
+tup6=(1, 2, 3)
+# tup6[0] = 10 # this will give us an error because tuples are
+# list are mutable so we can convert the tuple to a list, mutate the list, and then convert it back to a tuple
+list1=list(tup6) # this will give us a new list with the same elements
+print(list1)
+list1[0] = 10 # this will mutate the list by changing the first element to 10
+print(list1)
+

getStarted/python/01python/11_di.py

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+# Dictionaries
+letslearnuser={
+    "name":"saugat",
+    "age": 22,
+    "course":["python","django","js"]
+
+
+}
+print(letslearnuser)
+#couse python
+print(letslearnuser["course"][0]) # this will give us the first element of the course list which is python
+#length
+print(len(letslearnuser)) # this will give us the number of key-value pairs in the dictionary which is 3
+
+
+#modifying 
+letslearnuser["age"] = 23 # this will modify the value of the age key to 23
+
+#adding a new key-value pair
+letslearnuser["email"] = "saugat@example.com"
+print(letslearnuser)
+
+#keys
+keys=letslearnuser.keys() # this will give us a list of all the keys in the dictionary
+#keys after mutating 
+print(keys) # this will give us a list of all the keys in the dictionary after mutating it
+letslearnuser["name"] = "saugat shrestha" # this will modify the value of the name key to saugat shrestha
+letslearnuser["surname"] = "shrestha" # this will add a new key-value pair to the dictionary with the key surname and the value shrestha
+print(keys) # this will give us a list of all the keys in
+
+#values
+values=letslearnuser.values() # this will give us a list of all the values in the dictionary
+print(values) # this will give us a list of all the values in the dictionary
+letslearnuser["age"] = 24 # this will modify the value of the age key
+print(values) # this will give us a list of all the values in the dictionary after mutating it
+
+
+# items
+items=letslearnuser.items() # this will give us a list of all the key-value pairs in the dictionary as tuples
+print(items) # this will give us a list of all the key-value pairs in the dictionary
+letslearnuser["course"].append("react") # this will modify the value of the course key by appending react to the list
+print(items) # this will give us a list of all the key-value pairs in the dictionary after mutating it
+
+
+
+#if i want to acess the value name
+Items_dict=letslearnuser.items() # this will give us a list of all the key-value pairs in the dictionary as tuples
+print(Items_dict) # this will give us a list of all the key-value pairs in the dictionary
+
+# removing items
+letslearnuser.pop("surname") # this will remove the key-value pair with the key surname from the dictionary
+print(letslearnuser)
+#del
+del letslearnuser["email"] # this will remove the key-value pair with the key email from the dictionary
+print(letslearnuser)
+
+#clear
+letslearnuser.clear() # this will remove all the key-value pairs from the dictionary
+#del list
+del letslearnuser # this will delete the dictionary from memory
+
+#nested dictionary
+nested_dict={
+    "name":"saugat",
+    "age": 22,
+    "course":{
+        "python":"beginner",
+        "django":"intermediate",
+        "js":"advanced"
+    }
+}
+print(nested_dict)
+#acessing begainers
+print(nested_dict["course"]["python"]) # this will give us the value of the python key in the course dictionary which is beginner
+
+#copy 
+copy_dict=letslearnuser.copy() # this will give us a new dictionary with the same key-value pairs as letslearnuser
+print(copy_dict) # this will give us a new dictionary with the same key-value pairs as
+
+#copy using dict constructor
+copy_dict2=dict(letslearnuser) # this will give us a new dictionary with the same key-value pairs as letslearnuser
+print(copy_dict2) # this will give us a new dictionary with the same key-value pairs