@@ -12,20 +12,18 @@ def calculate_sum_and_product(input_numbers: List[int]) -> Dict[str, int]:
         "sum": 10, // 2 + 3 + 5
         "product": 30 // 2 * 3 * 5
     }
-    Time Complexity:
-    Space Complexity:
-    Optimal time complexity:
+    Time Complexity:There are two separate loops O(n)+O(n) total --->O(n)
+    Space Complexity:We have two variables sum and product O(1) total --->O(1)
+    Optimal time complexity: O(n) cannot be improved because we need to process each element at least once
+    but the code can be refactored for better readability.
     """
     # Edge case: empty list
     if not input_numbers:
         return {"sum": 0, "product": 1}
 
     sum = 0
-    for current_number in input_numbers:
-        sum += current_number
-
     product = 1
     for current_number in input_numbers:
+        sum += current_number
         product *= current_number
-
     return {"sum": sum, "product": product}